Correct. The slope of $\displaystyle{y}={x}+{5}\usepackage{cmbright}\Huge\$ is 1, so any line perpendicular to it will have slope -1 (the opposite reciprocal of 1). The equation $\displaystyle{y}-{2}=-{\left({x}-{1}\right)}\usepackage{cmbright}\Huge\$ is the point slope form of the line with slope -1 that goes through (1, 2).