Correct. The slope of $\displaystyle{y}=-{3}{x}-{4}\usepackage{cmbright}\Huge\$ is 3, so any line perpendicular to it will have slope $\displaystyle\frac{{1}}{{3}}\usepackage{cmbright}\Huge\$ (the opposite reciprocal of -3). The equation $\displaystyle{y}+{5}=\frac{{1}}{{3}}{\left({x}-{2}\right)}\usepackage{cmbright}\Huge\$ is the point slope form of the line with slope $\displaystyle\frac{{1}}{{3}}\usepackage{cmbright}\Huge\$ that goes through (2, -5).