Use the Fundamental Counting Principle to find the size of the sample space: $\displaystyle{2}\cdot{2}\cdot{6}={24}\usepackage{cmbright}\Huge\$

The event space is {(HH, 1), (HH, 3), (HH, 5)}.

The size of the event space is 3. The probability is: $\displaystyle\frac{{3}}{{24}}=\frac{{1}}{{8}}\usepackage{cmbright}\Huge\$