Correct. The slope of $\displaystyle{y}=-{2}{x}+{9}\usepackage{cmbright}\Huge\$ is -2, so any line perpendicular to it will have slope $\displaystyle\frac{{1}}{{2}}\usepackage{cmbright}\Huge\$ (the opposite reciprocal of -2). The equation $\displaystyle{y}-{3}=\frac{{1}}{{2}}{\left({x}-{2}\right)}\usepackage{cmbright}\Huge\$ is the point slope form of the line with slope $\displaystyle\frac{{1}}{{2}}\usepackage{cmbright}\Huge\$ that goes through (2, 3).