Correct. First note that $\displaystyle\frac{{9}}{{6}}=\frac{{12}}{{8}}=\frac{{15}}{{10}}\usepackage{cmbright}\Huge\$ , because these all reduce to $\displaystyle\frac{{3}}{{2}}\usepackage{cmbright}\Huge\$ .

So the ratio of corresponding sides is $\displaystyle\frac{{3}}{{2}}\usepackage{cmbright}\Huge\$ and therefore $\displaystyle{n}={2}\usepackage{cmbright}\Huge\$ .