Correct. The length of the the semicircle equals half the circumference of one circle.

$\displaystyle{C}=\frac{{\pi{d}}}{{2}}=\frac{{\pi\cdot{14}}}{{2}}\approx\frac{{\frac{{22}}{{7}}\cdot{14}}}{{2}}=\frac{{44}}{{2}}={22}\usepackage{cmbright}\Huge\$

Add the two sides of the triangle to this amount to find the entire perimeter of the composite figure: $\displaystyle{22}+{15}+{15}={52}\usepackage{cmbright}\Huge\$ inches.

The approximate perimeter of the composite figure is 52 inches.