Correct. A soup can is shaped like a cylinder, so use the formula $\displaystyle{V}=\pi{{r}}^{{2}}{h}\usepackage{cmbright}\Huge\$ . Can A has $\displaystyle{d}={8}\usepackage{cmbright}\Huge\$ , so $\displaystyle{r}={4}\usepackage{cmbright}\Huge\$ , and $\displaystyle{h}={15}\usepackage{cmbright}\Huge\$ . Can B has $\displaystyle{d}={10}\usepackage{cmbright}\Huge\$ , so $\displaystyle{r}={5}\usepackage{cmbright}\Huge\$ , and $\displaystyle{h}={12}\usepackage{cmbright}\Huge\$ .

Volume of Can A: $\displaystyle{V}=\pi{{\left({4}\right)}}^{{2}}{\left({15}\right)}=\pi{\left({16}\right)}{\left({15}\right)}\approx{3.14}\cdot{240}={753.6}\usepackage{cmbright}\Huge\$

Volume of Can B: $\displaystyle{V}=\pi{{\left({5}\right)}}^{{2}}{\left({12}\right)}=\pi{\left({25}\right)}{\left({12}\right)}\approx{3.14}{\left({300}\right)}={942}\usepackage{cmbright}\Huge\$

The difference in volume is about $\displaystyle{942}-{753.6}={188.4}\approx{188}\usepackage{cmbright}\Huge\$ cubic centimeters.