Correct. If $\displaystyle{y}+{3}={4}{\left({x}+{2}\right)},\usepackage{cmbright}\Huge\$ then $\displaystyle{y}+{3}={4}{x}+{8},\usepackage{cmbright}\Huge\$ so $\displaystyle{y}-{5}={4}{x},\usepackage{cmbright}\Huge\$ and therefore $\displaystyle-{5}={4}{x}-{y}.\usepackage{cmbright}\Huge\$