Correct. The line $\displaystyle{y}=\frac{{1}}{{2}}{x}-{4}\usepackage{cmbright}\Huge\$ has slope $\displaystyle\frac{{1}}{{2}}\usepackage{cmbright}\Huge\$ and its y-intercept is (0, -4). Therefore the points (0, -4) and (2, -3) are on the line.