The cosecant should be the reciprocal of the sine and the tangent should be the reciprocal of the cotangent. The correct answer is: $\displaystyle{\csc{{F}}}=\frac{{13}}{{5}}\usepackage{cmbright}\Huge\$ and $\displaystyle{\tan{{F}}}=\frac{{5}}{{12}}\usepackage{cmbright}\Huge\$